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mwilson23

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math question

FInd the LCM

6ab^2 ,9a^3 b
x^(2 ) z^(3 ),x^3 y ,y^2 z

Posted 44 day ago

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Answers (4)

jcatta21

The LCM for 6ab^2, 9a^3b is 18a^3b^2
The LCM for x^2, z^3, x^3, y^2, z is x^3y^2z^3

J.C

Posted 43 day ago

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math_fanatic

1) 6ab^2, 9ba^3

Step 1: Find the LCM of 6 and 9. The prime factorization of 6 is 3*2 and the prime factorization of 9 is 3*3.
The LCM is the multiplication of the of the prime factors multiplied together. If they have a prime factor in common, it is listed only once. The LCM is 3*3*2 = 18. (There are two threes because the 9 has two 3's
but the one from the 6 isn't listed since that 3 is one they have in common.)

Step2: Find the LCM of ab^2 and ba^3. They each have a factor of a and b so the LCM will be a to the largest exponent that appears and b to the largest exponent that appears: (a^3)(b^2)

Step 3: Combine results from step 1 and 2 to get LCM of original problem: 18(a^3)(b^2)

2) Find LCM of x^2, z^3, zy^3.
You can tell right away that the LCM is going to have to have factors x,y, and z in it. Just use the factors with the largest exponent attached to them and you will have your LCM: (x^2)(z^3)(y^3)

Posted 44 day ago

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1. The LCM of 6ab^2, and 9a^3b
first, find prime factors of numerical numbers.
then, take the all prime numbers with higher powers.
now, make the product of all prime numbers with higher powers.
similarly, make the product of all variables with higher powers.

now, prime facators of 6 and 9
6 = 2x3 and 9=3x3 ( here, x is multiplication sign )
now, all prime numbers are 2 and 3, so, the product of higher power of each prime no. is= 2x3x3=18,
similarly, from all variables the product of higher power of each variable= a^3b^2,

therefore, the LCM of 6ab^2 and 9a^3b=18a^3b^2

2. now, LCM of x^2z^3, x^3y and y^2z
= product of higher power of x, y and z.

therefore, the LCM = x^3y^2z^3

Posted 44 day ago

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jayteacher

To find the LCM, multiple the terms, then divide by the greatest common divisor (GCD).
I assume the first terms to find the LCM are 6ab^2 and 9a^3b
(6ab^2 • 9a^3b) / 3ab = 54a^4b^3 / 3ab = 18a^3b^2

(x^2 • z^3 • (x^3)y • (y^2)z) / (x^2)yz = (x^3)(y^2)(z^3)

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