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REGULAR PENTAGONAL PYRAMID

I see many explanations on the inter net re the formula for the LATERAL AREA of a regular pentagonal pyramid with a slant height of 6 with the length of each side of the base being 3 but don\'t understand a word of it, The answer choices are: 18, 9, 36, 45. Thank you.

719 day(s) ago

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jcatta21 		The regular pentagonal pyramid is a special solid that takes into account the pentagonal features of a three-dimensional geometric figure. Since a pentagon has 5 sides with general formula of 1/2(base)(5) = 5/2 * base, the lateral area of a regular pentagonal pyramid given a slanted height S = 6 and base = 3 along with given formula of a pentagon can be simplistically derived as follows:

Formula for Lateral Area of Pentagonal Pyramid = height * area of pentagon = S * (5/2 * base).

In this case the height (S = 6) && (base = 3) with number of side = 5 thus yielding the following lateral area of LA = 1/2 * (3) * (6) * (5) = 45.

Jcatta21

Posted 715 dy ago

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LATERAL AREA of any Pyramid = 1/2(Base)(height)(number of sides) =1/2(3)(6)(5) =45..............Ans

Posted 718 dy ago

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matherapist 		For a pyramid of any base (triangle, square, pentagon, hexagon) , The lateral area is the sum of the areas of the surface triangles with the base equal to the side of the base and a height equal to the slant height. The slant height is not equal to the height of the pyramid. For this problem, there are 5 triangles, and since it is a regular pentagon base, the base of each triangle is 3"". The height of each face is 6".
So find the area of a triangle of base 3" and height 6" and multiply by 5 since there are 5 of them.

Posted 719 dy ago

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